# Part A-June 2015

CSIR-UGC National Eligibility Test (NET) for Junior Research Fellowship and Lecturer-ship

Part A

PREVIOUS SOLVED QUESTIONS – 2015 June CSIR – NET EXAM

This time CSIR does not allow candidates to carry questions with them. We have collected maximum questions from our candidates (memory based).

1.     Two plane mirrors facing each other are kept at 60° to each other. A point is located on the angle bisector. The number of images of the point is
1.   6
2.   3
3.   5
4.   Infinite

Ans: 3
Expln:- [For more details refer Simple Instant Notes].

2.    I bout a shirt at 10% discount and sold it to a friend at a loss of 10%. If the friend paid me Rs. 729.00 for the shirt, what was the undiscounted price of the shirt ?
1. Rs.900
2. Rs.800
3. Rs.1000
4. Rs.911.25

Ans:-1[For more details refer Simple Instant Notes].

3.     What is angle x in the schematic diagram given below ? 1.   60
2.   50
3.   40
4.   30

Ans:- 4

Expln:- Sum of all angles of a triangle is 180° ie; 100 + 50 + 30 = 180[For more details refer Simple Instant Notes].

4. Information in DNA is in the form of sequence of 4 bases namely A, T, G and C. The proportion of G is the same as that of C, and that of A is the same as that of T. Which of the following strands of DNA will potentially have maximum diversity (i.e., maximum information content per base) ?

1.   length 1000 bases with 10% G
2.   length 2000 bases with 10% A
3.   length 2000 bases with 40% T
4.   Length 1000 bases with 25% C

Ans:- 4

Expln:- G + C content of DNA would give rise to the maximal information content (diversity) of protein.

5.    AB is the diameter of a circle. The chord CD is perpendicular to AB intersecting it at P. If CP = 2 and PB = 1, the radius of the circle is 1.   1
2.   2.5
3.   2
4.   5

Ans:- 2 More Questions & Answers Refer Simple Instant Notes